Let a be the first term , r be the common ratio, so a(ar)(ar^2)＝343 ==> (ar)^3 = 343 ==> ar = 7...
6,12,24,48,96 : general term = (6)(2^N-1) 若n=1, answer=(6)(2^0)=6 若n=5, answer=(6)(2^ 5-1)=(6)(2^4)=96
nonhomogeneous term = x為一次多項式, 故設(猜) yp= ax+b為解, 代入原方程式 0+ 3a+ax+b= x , 得 a= 1, b= -3, 故 yp=x-3為一特殊解 通解 y= yh+yp= c1 exp(-0.5x)+ c2 exp(-x) + x-3
1.) The 3rd term T(3) and 6th term T(6) of a G.P. are 400 and 6...1/3)]^3 T(1)=1600/6.25 (b) Find the sum of the first 6 terms S(6). S(6)=T(1)+T(2)+.......+T(6)=a(1+R...
少少幾項 or general terms ? 2013-04-09 22:58:08 補充： 1. 1/(1+sinx)= 1- sinx + (sinx)^2...2013-04-09 23:43:49 補充： 1/(1+x-x^3 /6 + ...): the first term of the quotient is 1 and the remainder is...
...because f(X) - Df(0)(X) equals the remainder term , which by Taylor's theorem is bounded in norm by C...
...3 = [2^(n+2) + (-1)^(n+1)] /3 ...... (答案) 這應是數列的通項問題（general term of series）， 而不是歸納法（induction）。
...6)x^2 + (7/3)x^3 + ..... So these are the first three non-zero terms of Mac series
