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  1. .... out .println("Original:"); y.printModel(); if (y. solve (0, 0)) { System. out .println("Solution:"); y.printModel(); } else ...

  2. ... scan = new Scanner(System.in); System. out .print("Enter the number of disks: "); n = ...

  3. ...[3]); y= a*x*x+b*x+c; System. out .println("y="+y); } } } 2009-05-01 14:56:56 補充: // Note! the above program solves by judging (1) whether (a, b, c) is inputted...

  4. ... the number of characters in a word } } System. out .println("Line number: " + lineCount); System...

  5. 這些東西任何一本C++語言的書 都會有解釋 可以像其他同學 借書來翻翻看

  6. #!/usr/bin/perl-w use strict; my ($aa,$bb,$cc); chomp ($aa=<STDIN>); chomp ($bb=<STDIN>); chomp ($cc=<STDIN>); my ($sol1,$sol2,$dec); if ($aa !=0){ $dec = $bb^2 - 4*$aa*$cc; $sol1 = (-$bb+$dec)/(2*$aa); $sol2 = (-$bb-$dec)/(2*$aa...

  7. ...100); } for (i = 1; i <= PSSs.length; i++) { System. out .print("Problem Solving Session " + i + ": "); PSSs[i-1] = input(scan, 0, 1...

  8. ...反過來求解 假設 center = (w/2, h/2) = (x0, y0) = p0 given p' = (x,y) solve the unknown p |p'-p0| = R = r^n |p-p0| = r = R^ (1/n) p = p0...

  9. 你問的另一題我答了scope rule。scope rule 規定了範圍,是compile time 處理的東東;lifetime是指它的生命期,是 run time的東東。除了上述的不同外,兩者大多情況下一樣;但不是永遠一樣。如:int func1(){}int LONG_LIFE;int func2(){ static int long_life;         int short_life;}這 2 個...

  10. ... prisonerXXX, I did not find out your bug. In fact I was too sleepy... saw your code. It's cool to solve it by recursive (or solve C(N, n) by recursive...