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a) Represent 6*10+0*102+3*1 by a denary numeral. 6*10+0*102+3*1 = 0*102 + 6*101 + 3*100 = 63 So the denary representation...
Represent each of the following by a binary numeral: (1) 1*(2*2)+1*2+1*1 = 1112 (2) 1*(2*2*2)+0*(2*2)+1*2+0*1 = 10102 ...
21a) ( 106 )^( 105 ) = 10^( 6 x 105 ) Then in total, the no. of numerals: 6 x 105 + 1 = 600001 ≈ 600000 600000cm = 6km If 1s is needed...
...16/16 = 1 " ....0 so answer is 101. 4. For quaternary, numerals are 0,1,2 and 3. Place values are 4^1, 4^2 etc...
5 = 1*2^2+0*2^1+1*2^0 = 101(base two) Note: For a number of base two, all digits can only be 1 or 0.