... What is the percent CdSO4 by mass in a 1.0 molal aqueous CdSO4 solution ? 解:設有此溶液一升,則其重量百分濃度如下: p=208.47/1208.47x100%=17...
...- (13) 6. C, strong acid must be less in mole than buffering solution 7. B, 777 g/mol dT = Kf * Cm (molality, mol/kg) Kf...
1.每公升酒精水溶液含100克CH3CH2OH,水溶液密度為0984g/cm3 (a)水溶液1公升=1000cm3=>質量=體積*密度=1000*0984=984g 其中水H2O=984-100=884g=0.884kg 酒精莫耳數=100/46=2.174mole (CH3CH2OH=46) 重量莫耳濃度Cm=溶質莫耳數/溶劑公斤數=2.174/0.884=2.46m (b)酒精在水溶液中的莫耳...