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  1. 1. Apply the equation: s = ut + (1/2) at ^2 to the vertical motion from R to S with s = -10m... is wrong because when the 2nd order max is at 15 degrees, the max order of fringe is 7, not 4...

  2. ...).l = NBl^2J (c) Torque produced by the object at the axle of the motor = mg x (6/100) = 0.06mg = 0.6m where g is the acceleration...

  3. ...3)^(2/3) AU = 17.83 AU (d) Because the distance from the sun at Q is shorter than that at R, the pontential energy of comet...

  4. ..., (c/co)^2 = 750/300 c/co = square-root(750/300) = 1.58 (c) New pressure at partition A, Pa = (n1)R(300)/(L1)A New pressure...

  5. ...the vertical motion of the ball after it is released, use: s = ut + (1/2) at ^2 with s = 0.5 m, u = 0 m/s, a = -g(=-10 m/s^2), t=? 0.5 = (1/2).(10)t^2 t...

  6. ...1.36 hence, c = 47.33 degrees (b) Let the refracted angle at the other side (inside the soap) at A be r r = (c - 10) degrees = (47...

  7. ... space, an isolated -ve charge produces -ve potential at its surrounding space. Thus, a +ve test charge under a +ve potential...

  8. ...distance between the highest point reached and the point reached at t1 be s by v^2-u^2=2as 0-(3)^2 = 2(-10)(s) s = 0.45m But the distnace...

  9. ...know that the two fragments are moving at opposite direction. (Each fragment has linear momentum...the answer made by Gabriella Montez ~ mock exam in progress" ^^ 希望你能明白我的邏輯,要完全...

  10. ...of the needle is pointing towards the back for the compass placed at the centre of the coil. For the other two, just treat the (small) section...