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  1. 排列方式

  1. 1. Toal dispalcement = 2 x (1/2) x 3 x 3^2 m = 27 m Average velocity = 27/6 s = 4.5 s Hence, only statement (2) is correct. 2. Let T be the tension in the ...

  2. ...method is a general technique for solving problems in statistical mechanics.The basic idea is to write the partition function in the form 圖片參考...

    分類:科學及數學 > 數學 2014年07月17日

  3. (i) Because pressure at valve exit = (0.5)pg = (1/2)p.v^2 where p is the density of coffee g is the acceleration due to gravity (= 9.81 m/s^2) v is the ...

  4. (i) Vertical speed of water jet on leaving nozzle = square-root[2g x 20] m/s = 19.81 m/s (Take g, the acceleration due to gravity, equals to 9.81 m/s^2) ...

  5. Density of oil = 0.85 x 1000 kg /m^3 = 850 kg /m^3 Dynamic viscosity of oil = 850 x (3.53 x 10^-4) Pa-s = 0.3001 Pa-s Area of one slant side of prism = ...

  6. On the level between x and y, consider the left tube of the manometer (i.e. the closed end one). Pressure at this level = pressure on oil surface of tank = ...

  7. Let P1 and P2 be the pressure at the lower and upper opening ends of the manometer tube respectively. Hence, P1 = P2 + (1.5 - 0.25)(po)g + 0.25(p')g ...

  8. ...)^2 gives (Vn)^2 = 94.31 (m/s)^2 By conservation of mechanical energy, gain in potential energy of water at top of water jet = loss of kinetic energy ...

  9. Apply Bernoulli's equation to the first floor and the basement, (Pb) + pg(Hb) + (1/2).(p)(vb)^2 = (P1) + pg(H1) + (1/2)(p)(v1)^2 where Pb and P1 are ...

  10. Let w be the width of the gate. Area of the vertical portion of the gate = wh Area of the horizontal portion of the gate = 1.5w Pressure at the vertical ...