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  1. a) Using the relation v = Rω, we have v = 0.11ω b) During sliding, the constant friction f continuously acts on the ball at the point of contact between ...

  2. Let the mass of block Y be m kg and with reference to the diagram below: 圖片參考:http://i388.photobucket.com/albums/z467/robert1973/Dec10/Crazymech1.jp ...

  3. ...k.e. of the block = 0.5 x 2 x 0.52 = 0.25 J So by conservation of mechanical energy, the max. e.p.e. stored in the spring is 0.25 = 0.1 = 0.15...

  4. For (1), since the man is climbing up, the moment about Q contributed by his weight is increasing since the perp. distance is increasing too. Therefore the ...

  5. Since the contact between P and Q is smooth, no friction can bring P into motion and hence the acc. of P will be zero. Therefore, all force component of F ...

  6. (a) In vertical motion part, its time of flight can be found as: s = ut + at2/2 with s = 200, u = 0 and a = 10 t = 6.32 s So, in horizontal direction, ...

  7. By Newton's Second Law of Motion, the acceleration of the trucks after the collision is given by : F = (M + m)(a) , where (M + m) and F are total mass ...

  8. Let the displacement from the point B be x. Since the object is slightly displaced, the displacement x has its value approximately equal to the ...

  9. The spring's compression will be maximum at the moment when the blocks have the same velocity. By conservation of linear momentum, the common velocity ...

  10. Let mass of the plank = M and the position of the men's shoulders' positions be X and Y with XA = 0.3 m and YB = 0.7 m, then: XY = 2 m XO = 1.2 m ...