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  1. ...include <math.h> //可算數學的函式 int main(void) { int m,i,h=0, leap =1; //宣告整數變數,有加等於的代表宣告時順便指定初始值 int a,b,r; //同上...

  2. ...;stdio.h> /*判別是否為閏年*/ #define IS_ LEAP _YEAR(Y) ((((Y)%400)==0)||((((Y...二月的日數是否需要修正*/ months[2]=IS_ LEAP _YEAR(y)?29:28; if((v>=1)&&(v&...

  3. if ( decide_ leap l ( year ) ) 此行( )內看不懂 說明:將輸入的year代入decide_leap1函式中 若是傳回值為1 則printf (“Method 1: %d is a leap year. n”, year); if ( decide_ leap 2 ( year ) ) 此行( )內看不懂 說明:將輸入的year...

  4. ...關係的 你問的 都是語法問題喔 @@ bool 是布林型態 只會有0與1兩種內容 至於 leap 複函式有啥功能 要看複函式內容阿 傳入int值 return布林值 enum是列舉型態的...

  5. ...;stdlib.h> #include <math.h> int main() { int m,i,h=0, leap =1; float k; printf(" n"); for(m=1;m<=1000;m++) { k=sqrt((double...

  6. ...even; 第三大題: 1. int n; for (i = 0;i <= n;++i) if (is_ leap _year(i)) printf("%d is leap year\n", i); 2. int n, count = 0...

  7. ...if(y%4==0 && y%400==0){ System.out.println(y+" a leap year"); }else{System.out.println(y+" a normal year"...

  8. ...out.print("輸入四位數的西元年: "); x = scan.nextInt(); boolean leap = false; if (x % 4 == 0) { leap = true; if (x % 100 == 0) { leap = false; if (x...

  9. ...; endl; system("pause"); } void No5(void) { int year; bool leap = 0; cout << "請輸入西元年份" <...

  10. ...int m[13]={0,31,28,31,30,31,30,31,31,30,31,30,31}; int year,month,day,w,i; void leap (int y) { if((y%400==0)||((y%4==0)&&(y%100!=0))) m[2]=29; } void print() { int...