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  1. ...hypercomplex number is simply: (1) a0 + a1 i1 + a2 i2 + ... + an in where n is a fixed integer, and a0, a1, a2, ... an are arbitrary...

    分類:科學及數學 > 數學 2009年03月12日

  2. (i) The commission earned on property with value of $585000 = 5% ($15000) + 3% ($45000) + 2.5% ($40000) + 2% ($585000 - $15000 - $45000 - $40000) = $750 + $1350 + $1000 + $9700 = $12800 The commission earned on property with value of $1085000 = 5% ($15000) + 3% ($45000) + 2.5% ($40000) + 2% ($1085000 - $15000 - $45000...

    分類:科學及數學 > 數學 2006年12月06日

  3. .... 2015-06-30 11:22:56 補充: Sorry, I think a particular dram means "指定的一次" So, the required prob...

    分類:科學及數學 > 數學 2015年07月04日

  4. Let X ~ Po(λ) be the number of customers arriving the first counter. Let Y ~ Po(λ) be the number of customers arriving the second counter. It is given that X...

    分類:科學及數學 > 數學 2015年05月12日

  5. Anna 是0.5 Sally 是0.7 Anna and Sally 是0.3 但不要忘是兩個人, 所以仲一個probability 是 Sally and Anna 的0.3

    分類:科學及數學 > 數學 2013年01月29日

  6. As two particular men should appear in the 5-men group, That equals to you have only 3 free seat that chosen from the remaining 7 people, so that is 7C3.

    分類:科學及數學 > 數學 2010年03月16日

  7. 1. His total income of that month =$(520+5264x25%) =$1836 2.Let y be the total number of candidates obtained grade C. y(100%-18%-38%)=77 y(44%)=77 y=175 Therefore, the total no. of candidates obtained grade...

    分類:科學及數學 > 數學 2006年12月05日

  8. (a) P(X on time) = 0.93 P(X late) = 1 - 0.93 = 0.07 P(Y on time) = 0.88 P(Y late) = 1 - 0.88 = 0.12 The required probability = P([Y late] and [X on time]) = P(Y late) x P(X on time) = 0.12 x 0.93 = 0.1116...

    分類:科學及數學 > 數學 2012年10月23日

  9. 2) (x+5)/x = (x+9)/(x+5) (x+5)^2 = (x+9)x x^2 + 10x + 25 = x^2 + 9x x = -25 -25, -20, -16 ------------------------------------------------------ 3) intensity of light at the surface = L deep at which the intensity of light only 5% of that at the surface = n L (1 - 3%)^n = 5% L (1 - 3%)^n = 5% 0.97^n = 0.05 n log 0.97 = log 0.05 n = 98...

    分類:科學及數學 > 數學 2010年04月14日

  10. ...easy to verify that any intersection of successor sets is a successor set; in particular , the intersection of all the successor sets is a successor set (it is...

    分類:科學及數學 > 數學 2009年12月06日