∫ 1/(x² + x - 2) dx, from 2 to ∞ = lim [t→∞] ∫ 1/(x² + x - 2) dx, from 2 to t = lim [t→∞] ∫ 1/[(x + 2) (x - 1)] dx, from 2 to t = lim [t→∞] ∫ { 1/[3(x - 1)] - 1/[3(x + 2)] } dx, from 2 to t = (1/3) lim [t→∞] [ ln|x - 1| - ln|x + 2| ] , from 2 to t = (1/3) lim [t→∞] ln[(t - 1)/(t + 2)] + (1/3) ln4 = 0 +(1/3) ln2²...
題目要求 "Set up, bur do not evaluate " , 也就是只列式, 不用後續求值. 以下兩小題皆可用 washer method. (a) 因為...
... chances of success. This article details how to evaluate , break down, and successfully complete math tasks and avoid getting stuck...
Sol lim(n->∞)_(1/n)｛Cos(π/n)+Cos(2π/n)+...+Cos[(n－1)π/n]｝ = lim(n->∞)_(1/n)Σ(k=0 to n－1)_Cos (kπ/n) =∫ (0 to 1)_Cos(πx)dxx =－(1/π)Sin(πx)｜(0 to 1) =－(1/π)(Sinπ－sin0) =0
Please Read： http://s13.postimg.org/psmr8iy2t/956.png
Sol x^2－4x+4=(x－2)^2 ∫(0 to 4) (x^2－4x+4)dx>=0
Sol d∫(0 to x)]Cos(t^2)dt/dx=Cos(x^2) lim x->0 _[∫(0 to x)]Cos(t^2)dt/x (0/0 type) =lim(x->0)_Cos(x^2) =1
Please Read： http://s11.postimg.org/i8khey83l/image.png
Please Read： http://s8.postimg.org/wnub5ktdf/image.png
Please read :
