...但沒有 local maximum. (Local maximum/minimum 都限定在定義域的內點.) 從 critical point 著手: f'(x) = 0 if and only if sin(x) = 0 或 cos(x) = -1. sin(x) = 0 發生...
... = 0, { ln(xy) - 4/x + 1 = 0 { (x - 4)/y = 0 x = 4, y = 1/4 The critical point is (4,1/4,0) fₓₓ(4,1/4) = 0.5 fᵧᵧ(4,1/4) = 0...
臨界點 ( critical point ) 包含以下三種: (1) 端點 (2) 奇異點 ( singular point ) , 即 f ' (x) 不存在...
..., 2015-04-15 11:51:23 補充： your attitude toward the job is the critical point , keeping positive thoughts can help the resolution of problems...
...bid to analyze the data in the questionnaires, we focused on some critical points so that people can understand what data we intended to investigate through ...
1.f'(t)=√(4-t^2)-t*0.5*2t/√(4-t^2)=[(4-2t^2)-t^2]/√(4-2t^2)=(4-3t^2)/√(4-2t^2)=0t^2=4/3 => t=+-2/√3=+-1.155=> Extreme fall on [-1,2] 2. f'(x)=101x^100+51x^50+1=0=> 0=101y^2+51y+1......y=x^50=> y=(-51+-√(2601-404))/202=(-51+-√2197)/202=(-51+-46.87)/202=(-97.87 -4.13)/202=(-0.4845 -0.0204)x=y^(1/50)=(-0.4845 -0.0204)^(1/50...
...08:53 補充： (2) f_x = 8x - 6 =0 => x = 3/4 f_y = 2y - 8 = 0 => y = 4 因此 critical point 在D以外，故本題只用考D的表面即4x^2 + y^2 =1 即原解中 r=1...
...in [0,2], f(x,3x) = x^2-2x(3x)+2(3x) = -5x^2+6x = h(x) (say)h'(x) = 6-10x, critical point : x = 3/5 h(0) = 0, h(2) = -20+12 = -8 (這兩個值已在 (1), (2) 中出現, h(0)=f...
