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  1. 1. black-box testing 指的是不必知道程式內部結構所進行的測試 答案中只有 D. Random testing 指輸入隨機產生,與程式內部無關 其他測試方法都針對程式內部的運作 2. 在 row-major 儲存方式中 X[3][2] 之前的儲存方式如下: X[1][1], X[1][2...

  2. ...or write in virtual memory. 2.data of BMP format is from down up to top approach , but JPEG(other) format is from top to down approach . so processing...

  3. 請描述"單字"的定義: cause caused causes 是同一字嗎? was, is 是同一字嗎? The, the 是同一字嗎? Apples, apple 是同一字嗎? 2014-06-01 23:11:26 補充: C++ 寫起來就很簡單了 C的話可能貼不下 2014-06-02 01:11:11 補充: #include...

  4. ...or write in virtual memory. 2.data of BMP format is from down up to top approach , JPEG(other) format is from top to down approach . so processing...

  5. ...03-09 20:45:24 補充: 2.data of BMP format is from down up to top approach , JPEG(other) format is from top to down approach . so processing...

  6. ...for all n>=2 (N0). lim |f(n)/g(n)| is constrained approaching +infinity (n+1)^5 = O(n^5) Q.E.D.

  7. ...adaptive planning, evolutionary development and delivery, a time-boxed iterative approach , and encourages rapid and flexible response to change. It is a...

  8. ... was at the mall wit yo friend I was scared to approach ya But then you came closer Hopin` you would give...

  9. ... was at the mall wit yo friend I was scared to approach ya But then you came closer Hopin' you would give...

  10. T(n)=3T(n/2)+O(n) wich can be solved to have T(n)=O(n^(3/2)). 上面的 3 是因為-- 本來這式子中有 4 個乘 (ac, ad, bc, 及 bd) uv = (a*2^(n/2) + b)*(c*2^(n/2) + d) = ac*2^(n/2) + (ad+bc) * 2^(n/2) + bd 但是, 當中的 (ad+bc), 本來兩個乘, 利用 ad+bc = (a+b)(c+d) - ac -bd, 可由已經得到的 ac...