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  1. fluid mechanics 相關
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  1. (i) Volume of box = (pi x 0.5^2) x 0.4 m^3 = 0.3142 m^3 Weight of box = 0.3142 x 900g N = 2827 N [Take g, the acceleration due to gravity, to be 10 m/s^2] ...

  2. (a) Upthrust acting on block A = (3.85 x 10^-3)pg where p is the liquid density and g is the acceleration due to gravity Hence, (3.85 x 10^-3)pg + 1.4g + ...

  3. Pressure difference at 8.2m of water = 8.2 x 1000g Pa = 82 000 Pa = 82 kPa where 1000 kg/m^3 is the density of water, and g is the acceleration due to ...

  4. ...orbit the Earth; for the formation of tides; for natural convection, by which fluid flow occurs under th

  5. (i) Because pressure at valve exit = (0.5)pg = (1/2)p.v^2 where p is the density of coffee g is the acceleration due to gravity (= 9.81 m/s^2) v is the ...

  6. (i) Vertical speed of water jet on leaving nozzle = square-root[2g x 20] m/s = 19.81 m/s (Take g, the acceleration due to gravity, equals to 9.81 m/s^2) ...

  7. Density of oil = 0.85 x 1000 kg /m^3 = 850 kg /m^3 Dynamic viscosity of oil = 850 x (3.53 x 10^-4) Pa-s = 0.3001 Pa-s Area of one slant side of prism = ...

  8. On the level between x and y, consider the left tube of the manometer (i.e. the closed end one). Pressure at this level = pressure on oil surface of tank = ...

  9. Let P1 and P2 be the pressure at the lower and upper opening ends of the manometer tube respectively. Hence, P1 = P2 + (1.5 - 0.25)(po)g + 0.25(p')g ...

  10. ...)^2 gives (Vn)^2 = 94.31 (m/s)^2 By conservation of mechanical energy, gain in potential energy of water at top of water jet = loss of kinetic energy ...